Coding 1
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Source
Code:
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#include <stdio.h>
#include <stdlib.h>
#include<conio.h>
int main(void)
{
int k, j=5, i=8;
float x=0.005;
float y=-0.01;
float z;
printf("++++++++++++++++++++++++++++++++++++++++++++++++++++++++++\n");
printf("+
Tugas 2 +\n");
printf("+ Nama : Fakhri Munziar +\n");
printf("+ NIM : 49013010 +\n");
printf("++++++++++++++++++++++++++++++++++++++++++++++++++++++++++\n\n");
printf("Diketahui\n");
printf("j=5, i=8 Dan k \n");
printf("x=0.005, y=-0.01 Dan z\n\n");
//1
printf("1. hasil dari (3*i-2*j)%(2*j-4) = %d\n",
(3*i-2*j)%(2*j-4));
printf("__________________________________________________________________\n");
//2
printf("2. hasil dari 2*((i/5)+(4*(j-3))%(i+j-2)) =
%d\n",2*((i/5)+(4*(j-3))%(i+j-2)));
printf("__________________________________________________________________\n");
//3
printf("3. hasil dari (i-3*j)%(12+2*j)/(x-y) = %d\n",(i-3*j)%(12+2*j)/(x-y));
printf("__________________________________________________________________\n");
//4 -(i + j )
printf("4. hasil dari -(i+j) = %d\n",
-(i+j));
printf("__________________________________________________________________\n");
//5
printf("5. Hasil dari ++i = k:%d i:%d\n",
++i);
printf("__________________________________________________________________\n");
//6
printf("6. Hasil dari i++ = k:%d i:%d\n", i++);
printf("__________________________________________________________________\n");
//7
printf("7. Hasil dari --j = k:%d j:%d\n",--j);
printf("__________________________________________________________________\n");
//8
printf("8. Hasil dari ++x = z:%f x:%f\n", ++x);
printf("__________________________________________________________________\n");
//9
printf("9. Hasil dari y-- = z:%f y:%f\n",
y--);
printf("__________________________________________________________________\n");
//10
printf("10. Hasil dari i<=j = %d\n",
i<=j);
printf("__________________________________________________________________\n");
//11
printf("11. Hasil dari x>=0 = %f\n",
x>=0);
printf("__________________________________________________________________\n");
//12
printf("12. Hasil dari x<y = %f\n",
x<y);
printf("__________________________________________________________________\n");
//13
printf("13. Hasil dari j!=6 = %d\n", j!=6);
printf("__________________________________________________________________\n");
//14
printf("14. Hasil dari (2*x+y)==0 = %f\n",
(2*x+y)==0);
printf("__________________________________________________________________\n");
//15
printf("15. Hasil dari 2*x+(y==0) = %f\n",
2*x+(y==0));
printf("__________________________________________________________________\n");
//16
printf("16. Hasil dari 2*x+y==0 = %f\n",
2*x+y==0);
printf("__________________________________________________________________\n");
//17
printf("17. Hasil dari !(i<=j) = %d\n",!(i<=j));
printf("__________________________________________________________________\n");
//18
printf("18. Hasil dari !(x>0) = %f\n",!(x>0));
printf("__________________________________________________________________\n");
//19
printf("19. Hasil dari (i>0)&&(j<5) =
%d\n",(i>0)&&(j<5));
printf("__________________________________________________________________\n");
//20
printf("20. Hasil dari (i>0)||(j<5) = %d\n",(i>0)||(j<5));
printf("__________________________________________________________________\n");
//21
printf("21. Hasil dari
(x>y)&&(i>0)||(j<5) = %d\n",(x>y)&&(i>0)||(j<5));
printf("__________________________________________________________________\n");
//22
printf("22. Hasil dari
(x>y)&&(i>0)&&(j<5) = %f\n",(x>y)&&(i>0)&&(j<5));
printf("__________________________________________________________________\n");
//23
printf("23. Hasil dari k=(i+j) = %d\n",
k=(i+j));
printf("__________________________________________________________________\n");
//24
printf("24. Hasil dari y-=x = %f\n",y-=x);
printf("__________________________________________________________________\n");
//25
printf("25. Hasil dari z=(x+y) = %f\n",z=(x+y));
printf("__________________________________________________________________\n");
//26
printf("26. Hasil dari x*=2 = %f\n",x*=2);
printf("__________________________________________________________________\n");
//27
printf("27. Hasil dari k=(x+y) = %d\n",k=(x+y));
printf("__________________________________________________________________\n");
//28
printf("28. Hasil dari i%=j = %d\n",i%=j);
printf("__________________________________________________________________\n");
//29
printf("29. Hasil dari i+=(j-2) = %d\n",i+=(j-2));
printf("__________________________________________________________________\n");
//30
printf("30. Hasil dari k=i=j = %d\n",k=i=j);
printf("__________________________________________________________________\n");
//31
printf("31. Hasil dari k=(j==5)?i:j = %d\n",k=(j==5)?i:j);
printf("__________________________________________________________________\n");
//32
printf("32. Hasil dari k=(j>5)?i:j = %d\n",k=(j>5)?i:j);
printf("__________________________________________________________________\n");
//33
printf("33. Hasil dari z=(x>=0)?x:0 = %f\n",z=(x>=0)?x:0);
printf("__________________________________________________________________\n");
//34
printf("34. Hasil dari z=(y>=0)?y:0 = %f\n",z=(y>=0)?y:0);
printf("__________________________________________________________________\n");
//35
printf("35. Hasil dari i-=(j>0)?j:0 = %d\n",i-=(j>0)?j:0);
printf("__________________________________________________________________\n");
system("pause");
return(0);
}
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Deskripsi
singkat:
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Pada soal ini digunakan fungsi operator
aritmetika. Dalam soal ini diketahuinilai variable j,i x,y yang mempunyai
nilai. Lalu program ini harus menampilkan sesuai yang diimginkan oleh soal
dan menampilkannya di layar.
   Berikut ini adalah video pembuatan programnya,chek this out!!! |
Selasa, 09 April 2013
TMD02,pemograman c, operator, ITB batch7, Fakhri Munziar
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